How do you solve the system #1 + t = 2s#, #-6 + 2t = 4 + s#, #2 + t = 1 + 2s#?

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Answer 1 · 2018-04-26T18:58:37

#s=4 , t=7#

#t=2s-1# ,if we make #t# the subject

Then substitute this into #-6+2t=4+s#

#=># #-6+2(2s-1)=4+s#

Expand the bracket

#=># #-6+4s-2=4+s#

Collect like terms

#=># #-8+4s=4+s#

Add 8 to both sides

#=># #4s=12+s#

Subtract #s# from both sides

#=># #3s=12#

Divide both sides by 3

#=># #s=4#

Substitute #s=4# into #1+t=2s#

#=># #1+t=2xx4#

#=># #t=7#