How do you solve the system #2x^2-4y=22# and #y=-2x+3#?
1 Answer
Substitute the right side of equation [2] for y in equation [1].
Solve the resulting quadratic for the two x values.
Use equation [2] to find the corresponding y values.
Explanation:
Given:
Substitute the right side of equation [2] for y in equation [1].
Solve the resulting quadratic for the two x values.
Use the distributive property:
Combine like terms:
Divide both sides by 2
Use equation [2] to find the corresponding y values.
The two points are: