# How do you solve the system 2x+3y=19 , 8x-3y=-4?

Mar 6, 2018

$y = \frac{16}{3}$
$x = \frac{3}{2}$

#### Explanation:

$2 x + 3 y = 19$ |
$8 x - 3 y = - 4$
First I added the two functions together canceling out -3y and 3y. we now have a function that resembles $10 x = 15$
dividing by 10 on both sides x= 3/2

Now multiply the first function by -4 equivalent to the original function
$- 8 x - 12 y = - 76$ |
$8 x - 3 y = - 4$
$- 15 y = - 80$