Question

How do you solve the system `2x + 3y = 2`, `x + 6y = 4`?

Answer 1

`y=2/3` and `x=0`

Explanation:

Multiply both sides of the second equation by 2 and subtract this new equation from the first equation. One gets the equation `-9y = -6`, or, equivalently, `y = 6/9 = 2/3` Substituting this value for y in equation 2 gives: `x + 6(2/3) = 4`, or `x-4=4`. So, x = 0.