# How do you solve the system  2x-3y=6 and -2x+3y=-6?

Jun 2, 2015

Given
$\text{[1] } 2 x - 3 y = 6$
$\text{[2] } - 2 x + 3 y = - 6$

Note that by adding [1] and [2], we get
$\textcolor{w h i t e}{\text{XXXXX}}$$0 = 0$

(The equations are really just different versions of each other so there is no single solution).

The best we could do is suggest the solution is the infinite set
$\textcolor{w h i t e}{\text{XXXXX}}$$\left\{\left(x , \frac{2}{3} x - 2\right) | \forall x \epsilon \mathbb{R}\right\}$