Question

How do you solve the system `2x - y = 2` and `-x + 5y = 3`?

Answer 1

`2x-y=2 => 2x-2=y`

`-x+5y=3 => -x+5*(2x-2)=3`

`-x + 10x -10 = 3 => 9x -10 = 3 => 9x = 13 => x= 9/13`

`y= 2x-2 => y= 2 * (9/13) - 2 = (18/13) - 2`

`= (18/13) - (26/13) = 8/13`