# How do you solve the system 2x - y = 3 and x + y = 3?

$x = 2$ $y = 1$
$2 x - y = 3$
$x + y = 3$
cancel $+ y$ and $- y$ then add $2 x + x$ and put it equal to $3 + 3$
then solve it and $x = 2$ after that put in equation 1 which is $2 x - y = 3$ now place the value of x in this equation $2 \left(2\right) - y = 3$ now solve the equation $4 - y = 3$
$- y = - 1$ cancel the minus sign and the ans will be $y = 1$