Question

How do you solve the system `-3x^2+y^2=9` and `-2x+y=0`?

Answer 1

See explanation.

Explanation:

From the second equation you can calculate variable `y`

`y=2x`

If you substitute `2x` for `y` in the first equation you get an equation with one variable `x`:

`-3x^2+(2x)^2=9`

`-3x^2+4x^2=9`

`x^2=9`

`x=-3vvx=3`

Now we can put the calculates values to find the corresponding values of `y`:

Answer: The system has 2 solutions:

`{(x=-3),(y=-6):}`

or

`{(x=3),(y=6):}`