How do you solve the system #-3x^2+y^2=9# and #-2x+y=0#?

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Answer 1 · 2018-03-27T07:29:15

See explanation.

From the second equation you can calculate variable #y#

#y=2x#

If you substitute #2x# for #y# in the first equation you get an equation with one variable #x#:

Now we can put the calculates values to find the corresponding values of #y#:

Answer: The system has 2 solutions:

or