How do you solve the system #3x-2y=2# and #5x-5y=10#?

1 Answer
Jun 10, 2015

Answer:

The solution for the system of equation is
# color(red)(x = -2 , y=-4#

Explanation:

#3x-2y=2# ,multiplying the equation by #5#
# 15x -color(red)( 10y) = 10#...........equation #1#

#5x-5y=10# , multiplying the equation by #2#
# 10x - color(red)(10y) = 20#.......equation #2#

Subtracting equation #1# from #2# to eliminate #color(red)(10y#
# 10x - cancelcolor(red)(10y) = 20#
# -15x +cancelcolor(red)( 10y) =- 10#

#-5x = 10#
#color(red)( x = -2#

Substituting #x# in equation #1# to find #y#
# 3x - 2 = 2y#
#(3x-2)/2 =y#

# y = (3.(-2) - 2)/2#
# y = -8/2 = -4#
# color(red)(y=-4#