How do you solve the system #3x/8-3y/5=33/80# and # 4x/7+4y/5=37/35#?

1 Answer
Jun 9, 2018

Answer:

Solution: # x = -24.38 , y= -17.3#

Explanation:

# 3 x/8 - 3 y/5 =33/80 or 3+x/8 -(3+y/5)=33/80# or

#cancel3+x/8 -cancel3-y/5=33/80# multiplying by #80# on

both sides we get, #10 x -16 y=33 (1)#

# 4 x/7 + 4 y/5 =37/35 or 4+x/7 +4+y/5=37/35# or

#8+x/7 +y/5=37/35# multiplying by #35# on

both sides we get, #280 +5 x +7 y=37 or 5 x +7 y= -243 (2)#

Multiplying equation (2) by #2# we get, #10 x +14 y= -486 (3)#

Subtracting equation (3) from equation (1) we get,

#-16 y- 14 y = 33 -(-486) or -30 y = 519 or y = -17.3#

Putting #y=-17.3# in equation (1) we get,

#10 x -16 *(-17.3)=33 or 10 x +276.8 =33# or

#10 x =33-276.8 or 10 x= -243.8 or x = -24.38#

Solution: # x = -24.38 , y= -17.3# [Ans]