# How do you solve the system  3x + y = 11 and –3x + 2y = 1 ?

...............$\cancel{3 x} + y = 11$
...........$\cancel{- 3 x} + 2 y = 1$
............$3 y = 12 \implies \underline{y = 4}$
$3 x + y = 11 \implies 3 x + 4 = 11 \implies 3 x = 7 \implies \underline{x = \frac{7}{3}}$