How do you solve the system #4x - 8y = 0# and #-3x + 8y = -7#?
1 Answer
May 31, 2015
4x - 8y = 0 -> x = (8y)/4 = 2y
-3x + 8y = -7 -> -6y + 8y = -7 -> 2y = -7 -> y = -7/2
x = -7.
Check: -28 + 56/2 = 0 OK