# How do you solve the system 4x-y=3y+7 and x+8y=4?

Apr 9, 2017

See below.

#### Explanation:

Let's first move the $y$'s to the left side in the first equation.

$4 x - y = 3 y + 7$
$4 x - 4 y = 7$

Dividing both sides by $4$,

$x - y = \frac{7}{4}$

Our other equation is:

$x + 8 y = 4$

Subtracting the first equation from the second, we get:

$9 y = \frac{9}{4}$

So $y = \frac{1}{4}$.

We plug this into one of the equations (I'm plugging into the second one).

$x + 2 = 4$
$x = 2$

So our ordered pair is: $\left(2 , \frac{1}{4}\right)$