Question

How do you solve the system `5x-7y=-16` and `2x+8y=26`?

Answer 1

`1) 5x-7y=-16`
`2) 2x+8y=26`

`2x=26-8y | *1/2`
`x=13-4y`

`-7y=-16-5x`
`7y=16+5x`
`7y=16+5(13-4y)`
`7y=16+65-20y`
`7y+20y=16+65`
`27y=81 | * 1/27`

`y=3`

`x=13-4(3)`
`x=1`

`y=3` and `x=1`

Explanation:

You can solve this system by finding what one variable equals from one of the equations, then put this into the other equation.

I went to find `y` here in the start. Because I saw that locking `x` by itself would be fair enough. It gave a clean `x=13-4y`, instead of fractions or such.

I then put what `x` equals to into the other `y` equation. So that I can find the integer value of `y` without having any `x` variables. Which gave the result of `y=3`.

From there, we can place the `y=3` into the other equation and find the `x` value, `x=13-4(3)` instead of `x=13-4y`. Which gave the result of `x=1`.

From that, we now know that:
`y=3` and `x=1`