How do you solve the system of equations #-10x+8y=2# and #-2x-4y=6# by elimination?

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Answer 1 · 2016-11-01T08:48:35

#x=-1=y#

#-10x+8y=2# #(i)#

#-2x-4y=6# #(ii)#

So we have 2 equations in 2 unknowns, a system that is in principle solvable.

If I add #(i)+2xx(ii)#, we get:

#-10x+8y-4x-8y=2+12#

i.e. #-14x=14#,

#x=(-14)/(14)=-1#

And, #y=-1#