How do you solve the system of equations #-3x + 10y = 11# and #- 8x + 2y = - 20#?

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Answer 1 · 2016-11-30T18:49:48

#x=3#

#y=2#

You can proceed by elimination of a variable:

#-3x+10y=11#
#-8x+2y=-20#

Multiply the second equation by #-5# then sum term by term:

#-3x+10y=11#
#40x-10y=100#

#37x =111#

gives:

#x=111/37=3#

Substitute the value of #x# in the second equation:

#-24+2y=-20#

#2y=4#

#y=2#