How do you solve the system of equations #3x - 2y = 1# and #4y=7+3x#?

1 Answer
Feb 28, 2017

Answer:

#x=3# and #y=4#

Explanation:

#3x-2y=1#
#4y=7+3x#

From the first equation, determine a temporary value for #3x#.

#3x-2y=1#

Add #2y# to both sides.

#3x=1+2y#

In the second equation, substitute #3x# with #color(red)((1+2y))#.

#4y=7+3x#

#4y=7+color(red)((1+2y))#

Open the brackets and simplify.

#4y=7+1+2y#

#4y=8+2y#

Subtract #2y# from both sides.

#2y=8#

Divide both sides by #@#.

#y=4#

In the first equation, substitute #y# with #color(blue)(4)#.

#3x-2y=1#

#3x-2(color(blue)(4))=1#

Open the brackets and simplify.

#3x-8=1#

Add #8# to both sides.

#3x=9#

Divide both sides by #3#.

#x=3#