How do you solve the system of equations #3x - 2y = 5# and #x = y + 2#?

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Answer 1 · 2016-11-14T20:11:19

#y=-1#
#x=1#

#3x−2y=5and x=y+2#

If we substitute #(y+2)# for #x#, we get:

#3(y+2)-2y=5=3y+6-2y=5#

Now we must collect the like terms to get #y# on its own:

#y=-1#

Now that we know the value of #y#, we can solve for #x#

#x=y+2=-1+2=1#

Just to make sure, we should plug our values back into one of the equations to check that we obtained the correct answer.

#3x-2y=3(1)-2(-1)=3+2=5#