How do you solve the system of equations #-3x+3y=4# and #-x+y=3#?

1 Answer
Apr 18, 2017

See the entire solution process below:

Explanation:

Step 1) Solve the second equation for #x#:

#-x + y = 3#

#color(red)(x) - x + y = color(red)(x) + 3#

#0 + y = x + 3#

#y = x + 3#

Step 2) Substitute #x + 3# for #y# in the second equation and solve for #x#:

#-3x + 3y = 4# becomes:

#-3x + 3(x + 3) = 4#

#-3x + (3 * x) + (3 * 3) = 4#

#-3x + 3x + 9 = 4#

#0 + 9 != 4#

#9 != 4#

Because #9# does not equal #4# there is no solution for these two equations which means they are parallel lines, with the same slope and not the same line.