How do you solve the system of equations: 4y=5x-1 and 3x-2y=1?
1 Answer
Aug 17, 2015
x = 1 ; y = 1
Explanation:
Re-write the equations as
4y - 5y + 1 = 0 -----------(1)
- 2y + 3x - 1 = 0 ----------(2)
Let us multiply equation (2) with 2 then
- 2y + 3x - 1 = 0 ----------(2)
# xx# 2 - 4y + 6x - 2 = 0 -------(3)
Take equations (1) and (3). Add (1) and (3)
4y - 5y + 1 = 0 -----------(1)
- 4y + 6x - 2 = 0 -------(3)
x -1 = 0
x = 1
Substitute (x = 1 ) in
4y = 5x - 1
4y = 5(1) -1 = 5 - 1 = 4
y =
y = 1
