How do you solve the system of equations #8x + 3y = - 4# and #5x + 2y = 6#?
1 Answer
Aug 2, 2017
Explanation:
I'll solve this by first eliminating the
Substitute back into one one of the original equations:
Let's check our answer via graphing (because the lines are so close to being parallel, I've had to really focus the graph):
graph{(8x+3y+4)(5x+2y-6)=0[-27,-25,66,70]}