How do you solve the system of equations #9x - 3y = 3# and #3x + 8y = - 17#?

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Answer 1 · 2017-03-10T14:55:04

#x=-1/3#

#y=-2#

Here we have two equations.

#9x-3y = 3 -># equation #1#

#3x+8y = -17 -># equation #2#

Multiply equation 2 by #3#, we get

#9x + 24y = -51 -># equation #3#

Subtract the new equation #3# from #1#

#9x - 3y = 3#

#-(9x +24y = -51)#

#0x -27 y = 54#

#=> y=-2#

Substitute in equation #2#

#3x + 8(-2) = -17#

#3x -16 = -17#

#3x = -1#

#x= -1/3#