How do you solve the system of equations #b= \frac { 3} { 4}a# and #a + b = 21#?

1 Answer
Mar 27, 2017

#a=12# and #b=9#

Explanation:

As #b=3/4a#, putting this value of #b# in #a+b=21#, we get

#a+3/4a=21#

or #7/4a=21#

or #7/4xx4/7a=21xx4/7#

and #a=21xx4/7=cancel21^3xx4/cancel7^1=12#

and #b=3/4xx12=3/cancel4^1xxcancel12^3=9#