# How do you solve the system of equations: x+y=2 and 2x-y=0?

Aug 5, 2015

I found:
$x = \frac{2}{3}$
$y = \frac{4}{3}$

#### Explanation:

You can add together the two equations (in columns) to get:
$\left\{\begin{matrix}x + y = 2 \\ 2 x - y = 0\end{matrix}\right.$
$3 x + 0 = 2$
So $x = \frac{2}{3}$
substitute back into the second equation:
$2 \cdot \frac{2}{3} - y = 0$
$y = \frac{4}{3}$