How do you solve the system of equations: x-y=3, x-2y=3?

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Answer 1 · 2015-08-14T11:37:00

The solutions for the system of equations is
#color(blue)(x=3,y=0#

# x-y=3#, multiplying this equation by #2#
#2x-color(blue)(2y)=6#.....equation #(1)#

# x-color(blue)(2y)=3#.......equation #(2)#

Now, we can solve through elimination as we have the term #color(blue)(2y) # common to both equations.

Subtracting equation #2# from equation #1#

#2x-cancel(color(blue)(2y))=6#
# -x+cancel(color(blue)(2y))=-3#

#color(blue)(x=3#

Now we substitute the value of #x# in equation #1# to find #y#
# x-y=3#
# x-3=y#

# color(blue)(y = 0#