How do you solve the system of equations y=x+3 and y=3x+5?

Nov 23, 2016

$x = - 1$ and $y = 2$

Explanation:

Because we are given $y = x + 3$ we can substitute $x + 3$ for $y$ in the second equation and solve for $x$:

$x + 3 = 3 x + 5$

$x + 3 - x - 5 = 3 x + 5 - x - 5$

$- 2 = 2 x$

$\frac{- 2}{2} = \frac{2 x}{2}$

$x = - 1$

We can now substitute $- 1$ for $x$ in the first equation to find $y$:

$y = - 1 + 3$

$y = 2$