How do you solve the system of linear equations $-3x + 2y = 8$ and $7x - 4y = 16$ ?

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Answer 1 · 2017-02-04T06:57:59

$x=32, y=52.$

Multiplying the $1^(st)" eqn. by "2" gives, "-6x+4y=16$ ,

and, adding this to the $2^(nd)$ eqn., we get,

$-6x+cancel(4y)+7xcancel(-4y)=16+16, i.e., x=32.$

Then, using this in the $1^(st)$ eqn., we get,

$-3(32)+2y=8 rArr-96+2y=8 rArr 2y=8+96=104$

$:. y=104/2=52.$

Hence, the Soln. $x=32, y=52.$

How do you solve the system of linear equations -3x + 2y = 8-3x + 2y = 8 and 7x - 4y = 167x - 4y = 16?