# How do you solve the system of linear equations y=-x+6 and y=3/4x-1?

Jul 15, 2016

Soln. : $x = 4 , y = 2$

#### Explanation:

Put the value of $y$ given by the First eqn. in the Second eqn. to get,

$- x + 6 = \frac{3}{4} x - 1 \Rightarrow 6 + 1 = \frac{3}{4} x + x \Rightarrow 7 = \frac{3 x + 4 x}{4}$

$\Rightarrow 7 = \frac{7}{4} x \Rightarrow 7 \cdot \frac{4}{7} = x \Rightarrow x = 4$

Putting $x = 4$ in the First eqn., we get #y=-4+6=2>

Hence, the soln. $x = 4 , y = 2$