How do you solve the system using the elimination method for 2x - 3y = 7 and 3x + y = 5?

Jul 30, 2015

I found:
$x = 2$
$y = - 1$

Explanation:

You can multiply the second equation by $3$:
{2x-3y=7
{color(red)(9x+3y=15 add the two together (in columns):
$11 x + 0 = 22$
so that $x = \frac{22}{11} = 2$
substitute this back into the first equation:
$2 \cdot 2 - 3 y = 7$
$y = - 1$