Question

How do you solve the system using the elimination method for 2x-y=-3 and x+3y =16?

Answer 1

I found:
`x=1`
`y=5`

Explanation:

Isolate, say, `x` from the second equation as:
`x=16-3y` (1)
Substitute for `x` into the first equation:
`2(16-3y)-y=-3`
`32-6y-y=-3`
`-7y=-35`
`y=(-35)/-7=5`
substitute this value into equation (1):
`x=16-3*5=1`