# How do you solve the system using the elimination method for -2x + y + 6 = 0 and 2x + y – 8 = 0?

Jul 9, 2015

I found:
$x = \frac{7}{2}$
$y = 1$

#### Explanation:

You can add directly the two equations to eliminate $x$:

{-2x+y+6=0
{2x+y-8=0 add them:

$0 + 2 y - 2 = 0$
so:
$y = \frac{2}{2} = 1$

substitute this value back into the first equation:

$- 2 x + 1 + 6 = 0$
$x = \frac{7}{2}$