# How do you solve the system using the elimination method for 3x – 2y – 7 = 0 and 5x + y - 3 = 0?

Jul 23, 2018

$x = 1 \mathmr{and} y = - 2$

#### Explanation:

Here ,

$3 x - 2 y = 7. \ldots \to \left(1\right)$

$5 x + y = 3. \ldots . . \to \left(2\right)$

Multiplying eqn. $\left(2\right)$ by $2$ and adding:

$i . e . \left(1\right) + 2 \times \left(2\right)$ we get

$3 x - \cancel{2 y} = 7$
ul(10x+cancel(2y)=6
$13 x + 0 = 13$

$\therefore x = 1$

Subst. $x = 1$ into $e q n . \left(2\right)$ we get

$5 \left(1\right) + y = 3$

$\therefore 5 + y = 3$

$\therefore y = 3 - 5$

$\therefore y = - 2$

Hence,

$x = 1 \mathmr{and} y = - 2$