# How do you solve the system using the elimination method for 3x+4y=18 and -2x+5y=34?

##### 1 Answer
Jul 18, 2015

I found:
$x = - 2$
$y = 6$

#### Explanation:

I would multiply the first equation by $2$ and the second by $3$ and add them (in columns):

{6x+8y=36
{-6x+15y=102 adding:
$0 + 23 y = 138$
So $y = \frac{138}{23} = 6$

using this value into the first equation gives you:
$3 x + 4 \cdot 6 = 18$
$3 x + 24 = 18$
$3 x = - 6$
$x = - \frac{6}{3} = - 2$