Question

How do you solve the system using the elimination method for R – 9S = 2 and 3R – 3S = -10?

Answer 1

I found:
`R=-4`
`S=-2/3`

Explanation:

I would multiply the first equation by `-3` to get:
`{-3R+27S=-6`
`{3R-3S=-10` add:
`0+24S=-16`
so:
`S=-16/24=-2/3`
substitute back into the first equation:
`R-9(-2/3)=2`
`R+6=2`
`R=-4`