How do you solve the system $x^{2} = 6 y$ $x^2=6y$ and $y = - x$ $y=-x$ ?

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Answer 1 · 2016-10-05T19:59:54

$x = - 6$ $x = -6$

As $y = - x$ $y = -x$ , $6 y = - 6 x$ $6y = -6x$

So $x^{2} = - 6 x$ $x^2 = -6x$

Therefore;

$x = - 6$ $x = -6$

Now we substitute $x$ $x$ into an earlier equation which still has $y$ $y$ in it.

$y = - x$ $y = color (blue)(-x)$

$y = - - 6$ $y = - color (blue)(-6)$

$y = 6$ $y = 6$

How do you solve the system x^2=6yx2=6yx^2=6y and y=-xy=−xy=-x?