# How do you solve the system x+y=4, x-y=2 ?

Mar 3, 2018

$x = 3$,$y = 1$

#### Explanation:

Using the first equation
$x + y = 4$
$y = 4 - x$
Then you substitute into the second equation
$x - \left(4 - x\right) = 2$
$2 x - 4 = 2$
$2 x = 6$
$x = 3$
Then you substitute x=3 into the first equation
$3 + y = 4$
$y = 1$