How do you solve the vector x given 6x-((2),(3))=4x+((-4),(-1))?

Jan 19, 2017

The answer is $x = \left(\begin{matrix}- 1 \\ 1\end{matrix}\right)$

Explanation:

Let's start

$6 x - \left(\begin{matrix}2 \\ 3\end{matrix}\right) = 4 x + \left(\begin{matrix}- 4 \\ - 1\end{matrix}\right)$

$6 x - 4 x = \left(\begin{matrix}- 4 \\ - 1\end{matrix}\right) + \left(\begin{matrix}2 \\ 3\end{matrix}\right) = \left(\begin{matrix}- 2 \\ 2\end{matrix}\right)$

$2 x = \left(\begin{matrix}- 2 \\ 2\end{matrix}\right)$

$x = \left(\begin{matrix}- 1 \\ 1\end{matrix}\right)$