How do you solve #u/5+6=2#?

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Answer 1 · 2016-09-26T02:12:09

#u=-20#

To solve this, let's first get the term with #u# on one side and the terms without #u# on the other by subtracting 6 from both sides:

#u/5+6=2#

#u/5+6-6=2-6#

#u/5=-4#

Now we can multiply both sides by 5:

#u/cancel5cancel(5)=-4(5)#

#u=-20#