How do you solve using the completing the square method #0=3x^2-11x+6#?

1 Answer
Apr 22, 2016

Answer:

#x=3#
#x=2/3#

Explanation:

Given -

#3x^2-11x+6=0#
Divide each term by the coefficient of #x^2#
#x^2-11/3x+2=0#
Take the constant term to the right
#x^2-11/3x=-2#
Divide the coefficient of #x#by #2# and add the
thus received value to both sides after squaring it.
#x^2-(11/3xx1/2)x+(11/6)^2=-2+(11/6)^2#
#x^2-11/6x+121/36=-2+121/36#
#x^2-11/6+121/36=((-72)+121)/36=49/36#
Take square root on both sides
#(x-11/6)=+-sqrt(49/36)=+-7/6#
#x=7/6+11/6=(7+11)/6=18/6=3#
#x=-7/6+11/6=(-7+11)/6=4/6=2/3#