How do you solve using the completing the square method #2x^2 - 4x -1=0#?
1 Answer
May 20, 2017
#x=1+sqrt(1.5)#
#x=1-sqrt(1.5)#
Explanation:
Given-
#2x^2-4x-1=0#
#2x^2-4x=1#
#(2x^2)/2-(4x)/2=1/2#
#x^2-2x=0.5#
#x^2-2x+1=0.5+1=1.5#
#(x-1)^2=1.5#
#x-1=+-sqrt(1.5)#
#x=1+-sqrt(1.5)#
