# How do you solve using the completing the square method  -2x^2 + 5x + 1/8 = 0?

Jul 20, 2016

$\frac{5 \pm \sqrt{26}}{4}$
${x}^{2} - \frac{5 x}{2} - \frac{1}{16} = 0$
${x}^{2} - \frac{5 x}{2} + \frac{25}{16} = \frac{1}{16} + \frac{25}{16} = \frac{26}{16}$
${\left(x - \frac{5}{4}\right)}^{2} = \frac{26}{16}$
$\left(x - \frac{5}{4}\right) = \pm \frac{\sqrt{26}}{2}$
$x = \frac{5}{4} \pm \frac{\sqrt{26}}{4} = \frac{5 \pm \sqrt{26}}{4}$