# How do you solve using the completing the square method -2x^2 - 7x + 4?

May 8, 2016

$- \frac{1}{2} \mathmr{and} 4$

#### Explanation:

Transform the equation for easier computation -->
$2 {x}^{2} + 7 x - 4 = 0$. Divide both sides by 2.
${x}^{2} + \frac{7 x}{2} = 2$
${x}^{2} + \frac{7 x}{2} + {\left(\frac{7}{4}\right)}^{2} = 2 + \frac{49}{16}$
${\left(x + \frac{7}{4}\right)}^{2} = \frac{81}{16}$
$\left(x + \frac{7}{4}\right) = \pm \frac{9}{4}$
$x = \frac{7}{4} \pm \frac{9}{4} = \frac{7 \pm 9}{4}$
x = 4 and $x = - \frac{2}{4} = - \frac{1}{2}$