# How do you solve using the completing the square method 4x^2-8=-13x?

Mar 11, 2016

x = - 13/8 +- 17.23/8

#### Explanation:

$4 {x}^{2} + 13 x = 8$
Divide the equation by 4 -->
$\left({x}^{2} + \frac{13 x}{4}\right) = 2$
${x}^{2} + \frac{13 x}{4} = 2$
${x}^{2} + \frac{13 x}{4} + \frac{169}{64} = 2 + \frac{169}{64}$
${\left(x + \frac{13}{8}\right)}^{2} = 2 + \frac{169}{64} = \frac{297}{64}$
$\left(x + \frac{13}{8}\right) = \pm \frac{17.23}{8}$

$x = - \frac{13}{8} \pm \frac{17.23}{8}$