# How do you solve using the completing the square method x^2-14x+5=0 ?

Apr 3, 2016

$x = 7 \pm 2 \sqrt{11}$

#### Explanation:

${x}^{2} - 14 x + 5 = 0$

$\implies {x}^{2} - 14 x = - 5$

$\implies {x}^{2} - 14 x + 49 = - 5 + 49$

$\implies {x}^{2} - 14 x + 49 = 44$

$\implies {\left(x - 7\right)}^{2} = 44$

$\implies x - 7 = \pm \sqrt{44} = \pm 2 \sqrt{11}$

$\therefore x = 7 \pm 2 \sqrt{11}$