# How do you solve using the completing the square method  x^2 + 16x = 0?

$\implies {x}^{2} + 2 x \cdot 8 + {8}^{2} - 64 = 0$
$\implies {\left(x + 8\right)}^{2} = 64 = {8}^{2}$
$\implies x + 8 = \pm 8$
$x = 0 \mathmr{and} x = - 8 - 8 = - 16$