How do you solve using the completing the square method #x^2 - 2x -3 = 0 #?
1 Answer
Mar 5, 2018
Explanation:
#0 = x^2-2x-3#
#color(white)(0) = x^2-2x+1-4#
#color(white)(0) = (x-1)^2-2^2#
#color(white)(0) = ((x-1)-2)((x-1)+2)#
#color(white)(0) = (x-3)(x+1)#
Hence:
#x = 3" "# or#" "x = -1#
