# How do you solve using the completing the square method x^2-2x-4=0?

Jul 19, 2016

$x = 1 \pm \sqrt{5}$
${x}^{2} - 2 x = 4$
${x}^{2} - 2 x + 1 = 4 + 1$
${\left(x - 1\right)}^{2} = 5$
$\left(x - 1\right) = \pm \sqrt{5}$
$x = 1 \pm \sqrt{5}$