Question

How do you solve using the completing the square method `x^2-4x=10`?

Answer 1

You take half of the number that's with the single `x`, and add the square of that to both sides.

Explanation:

`->x^2+2*(-2)x+(-2)^2=10+(-2)^2`

Or, after 'cleaning up':
`->(x-2)^2=14`

Then take the square root on both sides (do not forget the negative answer):
`->x-2=+-sqrt14->x=2+sqrt14orx=2-sqrt14`