How do you solve using the completing the square method x^2 + 8x + 13 =0?

Jul 27, 2016

$- 4 \pm \sqrt{3}$
${x}^{2} + 8 x + 13 = 0$
${x}^{2} + 8 x = - 13$
${x}^{2} + 8 x + 16 = - 13 + 16 = 3$
${\left(x + 4\right)}^{2} = 3$
$\left(x + 4\right) = \pm \sqrt{3}$
$x = - 4 \pm \sqrt{3}$