How do you solve using the elimination method #3x + 4y = 5#, #6x + 8y = 10#?
1 Answer
This system of equations has an infinite number of solutions.
Explanation:
Your system of equations looks like this
#{(3x + 4y = 5), (6x + 8y = 10) :}#
Notice that if you multiply the first equation by
#{(3x + 4y = 5 | * (-2)), (6x + 8y = 10) :}#
#{(-6x - 8y = -10), (6x " "+ 8y = " "10) :}#
#stackrel("---------------------------------------------")#
#" "0 " "+ 0 " "= 0#
Since you end up with
You can think of a system of equations as describing two lines. In your case, both equations decribe the same line, because if you multiply the first equation by
#{(6x + 8y = 10), (6x + 8y = 10) :}#
This implies that you have an infinite number of